How to download .msi file in Java -

-

i want download .msi file using java. have tried download file using following code

printwriter out = null; fileinputstream filetodownload = null; bufferedreader bufferedreader = null; try {         out = response.getwriter();         filetodownload = new fileinputstream(download_directory + file_name);         bufferedreader = new bufferedreader(new inputstreamreader(filetodownload));          //response.setcontenttype("application/text");         //response.setcontenttype("application/x-msi");         //response.setcontenttype("application/msi");         //response.setcontenttype("octet-stream");         response.setcontenttype("application/octet-stream");         //response.setcontenttype("application/x-7z-compressed");         //response.setcontenttype("application/zip");         response.setheader("content-disposition","attachment; filename=" +file_name );         response.setcontentlength(filetodownload.available());          system.out.println("\n file download starting");         string nextline = "";         while((nextline = bufferedreader.readline()) != null){             out.println(nextline);         }         out.flush();                                      } catch (ioexception e) {         out.write("<center><h2>the installer not available on server</h2></center>");         system.out.println("\n got exception while getting input stream file==>"+e);         log.error("error::", e);     }     finally{         if(null != bufferedreader){             try {                 bufferedreader.close();             } catch (ioexception e) {                 system.out.println("\n error in closing buffer reader==>"+e);                 log.error("error::", e);             }         }// end of if          if(null != filetodownload){             try {                 filetodownload.close();             } catch (ioexception e) {                 system.out.println("\n error in closing input stream==>"+e);                 log.error("error::", e);             }         }// end of if     }// end of

you can't read binary(msi) file readline() in case.your code totally wrong , not work. here simple function lets want.

    private void dodownload( httpservletrequest req, httpservletresponse resp,string filename, string original_filename )throws ioexception             {             file f = new file(filename);             int  length   = 0;             servletoutputstream op = resp.getoutputstream();             servletcontext context  = getservletconfig().getservletcontext();             string  mimetype = context.getmimetype( filename );             resp.setcontenttype( (mimetype != null) ? mimetype : "application/octet-stream" );             resp.setcontentlength( (int)f.length() );             resp.setheader( "content-disposition", "attachment; filename=\"" + original_filename + "\"" );             byte[] bbuf = new byte[bufsize];             datainputstream in = new datainputstream(new fileinputstream(f));             while ((in != null) && ((length = in.read(bbuf)) != -1)){             op.write(bbuf,0,length);             }             in.close();             op.flush();             op.close();         }

create dodownload() function in servlet , pass requierd parameters function doget,dopost or whatever valid place like.

parameters:

  • @param req request

  • @param resp response

  • @param filename name of file want download.

  • @param original_filename name browser should receive.


Comments

Post a Comment

Popular posts from this blog

c# - SVN Error : "svnadmin: E205000: Too many arguments" -

-
i trying reposotries using c# code process svncommand = null; var psi = new processstartinfo("svnadmin"); psi.redirectstandardoutput = true; psi.redirectstandarderror = true; psi.useshellexecute = false; psi.arguments= @"dump c:\repositories\myrepo > c:\temp\myrepodumpfile.dump"; using (svncommand = process.start(psi)) { var myoutput = svncommand.standardoutput; var myerror = svncommand.standarderror; debug.write("output :" + environment.newline + environment.newline + myoutput.readtoend() + environment.newline + "error :" + environment.newline + environment.newline + myerror.readtoend()); svncommand.close(); } when use dump command commandline svnadmin dump c:\repositories\myrepo > c:\temp\myrepodumpfile.dump it works fine when try ...
Read more

c++ - Using OpenSSL in a multi-threaded application -

-
i have been writing soap client application in c++ on ubuntu using openssl https transport , pthreads threading. have number of threads - 1 central data acquisition thread periodically gets worker threads make soap requests via shared mutex protected queues. reading documentation openssl found is openssl thread-safe? in openssl faq describes mechanisms required ensure thread safety when using openssl. implemented , works fine. the reason question conceptual difficulty really. thinking implementing same functionality application has already, instead of using threads, create 2 seperate applications : 1 worker thread (of multiple copies running) , main data acquisition thread. use tcp sockets communicate between 2 rather mutex protected queues. may bad idea not important - confusing me would have implement same functions required ensure openssl thread safety in second approach or not? my guess not have , treated independent (indeed surely must many applications use openssl) re...
Read more

All overlapping substrings matching a java regex -

-
is there api method returns (possibly overlapping) substrings match regular expression? for example, have text string: string t = 04/31 412-555-1235; , , have pattern: pattern p = new pattern("\\d\\d+"); matches strings of 2 or more characters. the matches are: 04, 31, 412, 555, 1235. how overlapping matches? i want code return: 04, 31, 41, 412, 12, 55, 555, 55, 12, 123, 1235, 23, 235, 35. theoretically should possible -- there obvious o(n^2) algorithm enumerates , checks substrings against pattern. edit rather enumerating substrings, safer use region(int start, int end) method in matcher . checking pattern against separate, extracted substring might change result of match (e.g. if there non-capturing group or word boundary check @ start/end of pattern). edit 2 actually, it's unclear whether region() expect zero-width matches. specification vague, , experiments yield disappointing results. for example: string line = "xx90xx"; strin...
Read more