sh - How can I assign command output to a variable in GNU make target rule? -

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at bash prompt, can following:

~/repo$ history_log=$(git log $(get_old_version)..$(get_new_version)); [[ ! -z ${histor_log} ]] && ( echo "some header"; echo "${history_log}" )

where git log demonstrably simplified version of have.

in make file have following command part of target:

$(output): $(input)         ...         echo "some header" > $(log_file)         git log $(shell get_old_version)..$(shell get_new_version) >> $(log_file)

how can rewrite make target behave bash command?

if following line-feeds being stripped:

$(output): $(input)         ...         history_log="$(shell git log $(shell get_old_version)..$(shell get_new_version))" ; \            [ -z "$${history_log}" ] && \              true || \               (echo "some header" ; echo "$${history_log}" )

when run looks like:

~/repo $ make commit 2b4d87b0e64d129028c1a7a0b46ccde2f42c5e93     author: jamie   <jamie@mymail.com>   date:   mon jun 25 18:46:27 2012 -0400              issue #468: sucker's been sped up.

and prefer be:

~/repo $ make commit 2b4d87b0e64d129028c1a7a0b46ccde2f42c5e93      author: jamie   <jamie@mymail.com> date:   mon jun 25 18:46:27 2012 -0400       issue #468: sucker's been sped up.

i think issue make executes commands in /bin/sh , not /bin/bash. regardless i'm looking portable solution if there one.

make's shell eating newlines. stop using it. instead of $( shell get_old_version ), escape $:

$$( get_old_version )

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