awk split integer into several parts -

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i have integer 20120305193821 , split several parts 2012-03-05-19:38:21 further usage in awk. can help?

if using gawk, can use fieldwidths:

echo 20120305193821 | gawk '{printf "%s-%s-%s-%s:%s:%s\n",       $1, $2, $3, $4, $5, $6}' fieldwidths="4 2 2 2 2 2"

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