regex - Format a file based on the IFS -

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i using sed concatenate contents of file as:

    cat source.c |  sed -e :a -e '$!n; s/\n/ /; ta'

the file contains relevant informations [ series of strings ] separated pipe |. want change ifs pipe |and output may piping new ifs thereby displaying new formatted file stdout.

an instance of source.c after concatenation :

    void f0 (***) | void f1 (***) | void f2 (***)| void f3 (***)

what hope achieve setting ifs :

    void f0 (***)     void f1 (***)     void f2 (***)     void f3 (***)

thanks in advance replies .i not sure if possible files , , dont want involve variables or arrays here .

edit : source file appears in beginning :

    void            f0           (***) |     void                 f1                               (***) |                    void                   f2                    (***) |     void             f3                                                (***)

so first concatenate double space each word group , split using pipe delimiter .

sed -e :a -e '$!n; s/\n/ /; ta' source.c | sed -e 's/  */  /g' -e 's/ *//'

the sed , awk alternative job .

answer selected based on upvotes @ time of first edit :) . suggested in 1 of answers leaving question unchanged in order others find these uncomplicated alternatives instead of messing ifs.

if that's want, replace '|' newlines.

echo 'void f0 (***) | void f1 (***) | void f2 (***)| void f3 (***) ' | sed 's, *| *,\n,g'

or command:

sed -e :a -e '$!n; s/\n/ /; ta' source.c | sed 's, *| *,\n,g'

messing shell's ifs can obscure problems. messing awk's not problem though:

echo 'void f0 (***) | void f1 (***) | void f2 (***)| void f3 (***) ' | awk 'begin {rs="|";} { print $0}' sed -e :a -e '$!n; s/\n/ /; ta' source.c | awk 'begin {rs="|";} { print $0}'

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