Python continue from the point where exception was thrown -

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hi there way continue point exception thrown? eg have following psudo code

unique code 1 unique code 2 unique code 3

if want ignore exceptions of of unique code statements have this:

try:   #unique code 1 except:   pass  try:   #unique code 2 except:   pass  try:   #unique code 3 except:   pass

but isn't elegant me, , life of me can't remember how resolved kind of problem last time... want have like

try:   unique code 1   unique code 2   unique code 3 except:   continue last exception raised

updated： reason: reason asking above 3 lines of code share same kind of exceptions, lets say, extract information array, , in particular scenario don't care exception of value not in array.

wrap each of code sections function , try calling each in for-loop:

def code1():     #unique code 1  def code2():     #unique code 2  def code3():     #unique code 3  section in [code1, code2, code3]:     try:         section()     except:         pass

edit: if still looking way, use decorator make each call "safe" buy returning errors instead of throwing them. not sure if pythonic or great way things way:

def safe_call(fn):     def wrapper(*args, **kwargs):         try:             return fn(*args, **kwargs)         except exception error:             return error     return wrapper  @safe_call def code1():     #unique code 1  @safe_call def code2():     #unique code 2  @safe_call def code3():     #unique code 3  code1() code2() code3()

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