Lua Pattern - How get the required string using this lua pattern -

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local invoicedata = [[i n v o c e invoice no. : abcdefg125469857 invoice date may 2012 ]]

the pattern using 

 print (string.match(invoicedata,'\ninvoice date (.-)\n'))

i want fetch string invoice date may12. or 0512.. please help

thanks

instead of matching .-, more specific , use %w+ (alpha-nums) , %d+ (digits) match month , year.

the script:

local invoicedata = [[i n v o c e invoice no. : abcdefg125469857 invoice date may 2012 ]]  month, year = string.match(invoicedata,'invoice%s+date%s+(%w+)%s+%d*(%d%d)') print(month, year)

will print:

may    12

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